Conservation of Energy Theorem

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Questions beginning with "cont...." follow on from the previous question.


1) Compute the potential energy of the 10 Kg block with respect to the datum.

V = ?

One answer only.
   98.1 J
   -98.1 J
   196.2 J
   -196.2 J
   None of the above

2) Compute the potential energy of the 10 Kg block with respect to the datum.

V = ?

One answer only.
   40 J
   80 J
   20 J
   -80 J
   None of the above

3) The 10 Kg block is released from rest at A. Select the equation that represents the reduced form of the conservation of energy theorem, necessary to determine the maximum compression h in the spring at B. Place the datum at A.

One answer only.
   0 = -98.1h - 98.1 - 50h2
   0 = -98.1h + 50h2
   0 = -98.1 - 98.1h + 50h2
   0 = -98.1 - 50h2
   None of the above

4) The 10 Kg block is moving freely down the smooth curved path with a speed of 2 m/s when it is at A. Select the equation which represents the reduced form of the conservation of energy theorem, necessary to determine the block's speed at B. Place the datum at A.

One answer only.
   20 = 5vB2 - 98.1(3 - 3cos45)
   -20 = 5vB2 + 98.1(3 + 3cos45)
   20 = 5vB2 + 98.1(3 - 3cos45)
   20 = -5vB2 - 98.1(3 - 3cos45)
   None of the above

5) The collar has a mass of 10 Kg and slides along the smooth rod. When it is at A it has a downward velocity of 2 m/s. If the spring has an unstretched length of 1 m, select the equation which represents the reduced form of the conservation of energy theorem, necessary to determine the collar's speed when it is at B. Place the datum at A.

One answer only.
   1580 = 5vB2 + 10(9.81)(4) - 400
   1620 = 5vB2 + 10(9.81)(4) + 400
   1620 = 5vB2 - 10(9.81)(4) + 400
   1620 = 5vB2 - 10(9.81)(4) - 400
   None of the above

6) The spring is compressed 0.2 m and released when the 2 Kg bob is resting on it at A. Select the equation that represents the reduced form of the conservation of energy theorem, necessary to determine the bob's speed when it reaches B. Place the datum at A.

One answer only.
   40 = vB2 - 3(9.81)
   40 = vB2 +4.5(9.81)
   40 = vB2 + 3(9.81)
   40 = vB2
   None of the above


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