1) The block has a mass of 0.4 Kg and is subjected to a uniform circular motion about the vertical axis. If the tensile strength of the cord AB is 200N, calculate the constant speed of the block that will break the cord. Neglect friction.

v = ?

   5 m/s

   10 m/s

   25 m/s

   50 m/s

   None of the above

2) The block has a mass of 2 Kg and is held up against the wall of the rotating surface by centrifugal force. If the coefficient of static friction between the block and the wall is m_s = 0.3, select the equation of the motion for the block in the b direction.

   0.3N_B - 19.62 = 0

   0.3N_B - 19.62 = 2a_b

   0.3N_B - 19.62 = -2a_b

   0.3N_B + 19.62 = 2a_b

   None of the above

3) The 10 Kg block is resting on the rotation platform. At the instant shown the block's tangential speed is 2 m/s, and the speed is increasing at 1 m/s². If the surface of the platform is rough, calculate the magnitude of the frictional force acting on the block in the t direction.

F_t = ?

   30 N

   40 N

   68.1 N

   98.1 N

   None of the above

4) The 10 Kg block is travelling along the smooth path. Calculate its greatest speed at A so it does not leave the path. The radius of curvature at this point is r= 2 m.

v = ?

   19.62 m/s

   (9.81)^1/2 m/s

   (19.62)^1/2 m/s

   2(9.81)^1/2 m/s

   None of the above

5) The 10 Kg block is released from rest at A and slides down along the smooth curved path. Select the equation of motion for the block in the t direction.

   98.1sinq = 10a_t

   -98.1sinq = 10a_t

   98.1cosq = 10a_t

   -98.1cosq = 10a_t

   None of the above

6) Cont....Select the equation of motion for the block in the n direction.

   N_B - 98.1sinq = 5v²

   N_B - 98.1cosq = 10v²

   98.1cosq - N_B = 5v²

   N_B + 98.1sinq = 5v²

   None of the above